pembahasan soal limit fungsi trigonometri 1

Pembahasan soal limit fungsi trigonometri 1

$1.\;\;\displaystyle\lim_{x\to 0}\left(\frac{sin^22x}{tan^23x}\right)$

$2.\;\;\displaystyle\lim_{x\to 1}\left(\frac{\left(3x+1\right)sin(x-1)}{x^2+2x-3}\right)$

Pembahasan

$1.\;\;\displaystyle\lim_{x\to 0}\left(\frac{sin^22x}{tan^23x}\right)=\frac{2^2}{3^3}=\frac{4}{9}$

$2.\;\;\displaystyle\lim_{x\to 1}\left(\frac{\left(3x+1\right)sin(x-1)}{x^2+2x-3}\right)$

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